Question
The ratio of quantity of milk and water in a 300 litres
mixture is 6:4, respectively. On removing 'M' litres of mixture the difference between the quantities of milk and water becomes 50 litres. Find the value of 'M'.Solution
ATQ, After removing 'M' litres of mixture, let quantity of milk and water left be 6x litres and 4x litres, respectively. According to the question, 6x - 4x = 50 Or, 2x = 50 Or, 'x' = 50 / 2 = 25 Therefore, after removal of 'M' litres of mixture, quantity of mixture left = 6x + 4x = 10x = 10 Ć 25 = 250 litres Therefore, 'M' = 300 - 250 = 50
If SecA + TanA = 2√2 + 9, then find the value of Sin A + Cos A.
What is the value of [(sin x + sin y) (sin x ā sin y)]/[(cosx + cosy) (cosy ā cosx)]?
If ā3āÆtanāÆx = 3, then the value of x:
If cos²α + cos²β = 2, then the value of tanā“α + sināøβ is
which of the following is equal to [(tan Īø +secĪø -1)/ (tanĪø-secĪø +1)]Ā Ā
Find the value of:Ā (Sin2 60 Ā° X cos 30 Ā° X sec 60Ā°)/tan 30Ā°
Ā If sin Īø = 3/5 and cos Īø = 4/5, find the value of (2tanĀ² Īø + 3cotĀ² Īø).
If A and B are complementary angles, then the value of-
sin A cos B + cos A sin B – tan A tan B + sec 2
