Question
A certain quantity of a 35% sugar solution is mixed with
10 liters of a 48% sugar solution to obtain a 40% sugar solution. How many liters of the 35% sugar solution were in the mixture?Solution
Let Q liters of a 35% sugar solution be mixed with 10 liters of a 48% sugar solution to obtain 40% sugar. In Q liters, the quantity of sugar = Q × 35% = 0.35Q liters In 8 liters, the quantity of sugar = 10× 48% = 10 × 0.48 = 4.80 liters According to the question, 0.35Q + 4.8 = (10 + Q) × 40%  0.35Q + 4.8 = (10 + Q) × 0.4  0.35Q + 4.8 = 4 + 0.4Q  0.4Q - 0.35Q = 4.8 - 4  0.05Q = 0.8 Q=.8/.05 Q=16 liters
625, 5, 125, 25, 25, ? , 5
21 23 26 ? 39 51
...Identify the logic of the below given series and given answer.
Series I :: 1840, 1719, (P), 1694, 1890, 1665, 1921
Series II :: 175, 4...
96Â Â Â 111Â Â Â 131Â Â Â ? Â Â Â Â Â 186Â Â Â Â 221
Choose the correct alternative
21: 3 ∷ 574: ?
A sequence {Tₙ} is defined by: Tₙ = a·n² + b·n + c for all positive integers n, where a, b, c are constants.
It is known that - Tâ‚‚ = 11,...
16    9    11   26    ?    912
The number of terms in the sequence 20, 25, 30, ….., 160 is:
70    191    47    216    ?    245
12 78 385 ? 4629 9260
...
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