A mixture P, consisting of 648 ml, contains milk and honey in the ratio of 5:4. This is combined with another mixture Q, which has a milk to honey ratio of 10:3. The resulting mixture has a honey quantity 25% less than the milk quantity. Determine the quantity of mixture Q.
ATQ, Quantity of milk in 648 ml of mixture P = 5/9 × 648 = 360 ml Quantity of Honey in 648 ml of mixture P = 4/9 × 648 = 288 ml Let quantity of milk and Honey in mixture Q is 10a ml and 3a ml respectively. According to question; (360 + 10a)/(288 + 3a) = 4/3 1080 + 30a = 1152 + 12a Or, 18a = 72 Or, a = 4 Desired answer = 13a = 13 × 4 = 52ml
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