128 litres of mixture ‘A’ (milk + water) contains 32 litres more water than milk. If 25% of mixture ‘A’, 70 litres of milk and 80 litres of water are added in an empty jar, then the quantity of milk is what percentage of the quantity of water in the jar?

Solution

Let the quantity of milk in mixture ‘A’ = ‘y’ litres Then, quantity of water in mixture ‘A’ = (y + 32) litres So, y + y + 32 = 128 Or, 2y = 128 – 32 = 96 Or, y = 96/2 = 48 So, quantity of milk in mixture ‘A’ = 48 litres And, quantity of water in mixture ‘A’ = 48 + 32 = 80 litres Quantity of milk in 25% of mixture ‘A’ = 48 × 0.25 = 12 litres Quantity of water in 25% of mixture ‘A’ = 80 × 0.25 = 20 litres So, quantity of milk in the jar = 12 + 70 = 82 litres Quantity of water in the jar = 80 + 20 = 100 litres So, required percentage = (82/100) × 100 = 82%