Question
128 litres of mixture βAβ (milk + water) contains 32
litres more water than milk. If 25% of mixture βAβ, 70 litres of milk and 80 litres of water are added in an empty jar, then the quantity of milk is what percentage of the quantity of water in the jar?Solution
Let the quantity of milk in mixture βAβ = βyβ litres Then, quantity of water in mixture βAβ = (y + 32) litres So, y + y + 32 = 128 Or, 2y = 128 β 32 = 96 Or, y = 96/2 = 48 So, quantity of milk in mixture βAβ = 48 litres And, quantity of water in mixture βAβ = 48 + 32 = 80 litres Quantity of milk in 25% of mixture βAβ = 48 Γ 0.25 = 12 litres Quantity of water in 25% of mixture βAβ = 80 Γ 0.25 = 20 litres So, quantity of milk in the jar = 12 + 70 = 82 litres Quantity of water in the jar = 80 + 20 = 100 litres So, required percentage = (82/100) Γ 100 = 82%
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