Question
A 152-litre mixture contains petrol and water, only in
ratio 3:2, respectively. How much water should be added in the mixture so that the quantity of water becomes 48% of quantity of resultant mixture?Solution
Quantity of water in the initial mixture = 152 × (2/5) = 60.8 litres Quantity of petrol in the initial mixture = 152 × (3/5) = 91.2 litres Since, we’re not adding petrol, 91.2 litres of petrol will represent 48% of the new mixture. So, total quantity of resultant mixture = 91.2 ÷ 0.48 = 190 litres Quantity of water to be added = 190 – 152 = 38 litres
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44   45    41   50    ?      59    23
...221, 100, 0, -81, ?
...900 Â Â Â 90Â Â Â 18Â Â Â ? Â Â Â Â 2.16Â Â Â Â 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187
