Question
A 152-litre mixture contains petrol and water, only in
ratio 3:2, respectively. How much water should be added in the mixture so that the quantity of water becomes 48% of quantity of resultant mixture?Solution
Quantity of water in the initial mixture = 152 × (2/5) = 60.8 litres Quantity of petrol in the initial mixture = 152 × (3/5) = 91.2 litres Since, we’re not adding petrol, 91.2 litres of petrol will represent 48% of the new mixture. So, total quantity of resultant mixture = 91.2 ÷ 0.48 = 190 litres Quantity of water to be added = 190 – 152 = 38 litres
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