Question
In container P, there is 100 litres of milk and in
container Q there is 50 litres of water. 25% of milk and 40% of water is taken out from the respective containers and are mixed in container R. How much water should be added to container R such that the ratio of milk to water becomes 5:7? MTSolution
Quantity of milk in container R = 0.25 × 100 = 25 litres Quantity of water in container R = 0.40 × 50 = 20 litres Let x litres of water is added to the container R. According to the question, 25/(20 + x) = 5/7 Or, 175 = 100 + 5x Or, 5x = 75 Or, x = 15 Therefore, water added to container R = 15 litres
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â