Question
In 81 litres of a mixture (milk + water), ratio of
quantity of milk to that of water in a mixture is 4:5, respectively. (3x + 11) litres of milk and 25 litres of water is added to the mixture such that the quantity of milk in the resultant mixture is 40% more than that of water in it. Find the value of ‘x’.Solution
Initially, Quantity of milk in the mixture = 81 × (4/9) = 36 litres Quantity of water in the mixture = 81 – 36 = 45 litres According to the question, 1.40 × (45 + 25) = 36 + 3x + 11 => 98 = 47 + 3x => x = 17
542Â Â Â Â Â Â 541Â Â Â Â Â Â Â 532Â Â Â Â Â Â Â 507 Â Â Â Â Â Â Â 458Â Â Â Â Â Â Â ?
...1Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â 13Â Â Â Â Â Â Â Â Â Â Â Â 25Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 41Â Â Â Â Â Â Â Â Â ...
6 2 8 ? 84 416
...Find the odd one out: 11, 13, 17, 19, 21
3, 7, 16, 35, ?, 153
20    60      180      540     ?     4860
...218, 108, 160, ? , 1385.50
73920, 9240, ?, 220, 44, 11
21    23    49    152    ?     3086
If  2,  7, 20,  x ,  110,  235,
Then,  7 x + 7√x = ?
