Question
In 81 litres of a mixture (milk + water), ratio of
quantity of milk to that of water in a mixture is 4:5, respectively. (3x + 11) litres of milk and 25 litres of water is added to the mixture such that the quantity of milk in the resultant mixture is 40% more than that of water in it. Find the value of ‘x’.Solution
Initially, Quantity of milk in the mixture = 81 × (4/9) = 36 litres Quantity of water in the mixture = 81 – 36 = 45 litres According to the question, 1.40 × (45 + 25) = 36 + 3x + 11 => 98 = 47 + 3x => x = 17
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3 × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2
15% of 1800 + 22 = ?
