Question
A jar contains a mixture of orange juice and water in
the ratio of 4:1. 75 litres of the mixture was taken out and 25 litres of water was added to it. If the water was 40% in the resultant mixture, what was the initial quantity of the mixture in the jar?Solution
Orange : water 4x : x Total = 5 x 75 litre of mixture taken out, Orange = 4x/5x × 75 = 60 Orange in mixture = 4x – 60 Water in mixture = x/5x × 75 = 15 Water = (x – 15) + 25 = x + 10 According to the question, (x+10)/(4x-60) = 40/60 6x + 60 = 16x – 240 10x = 300 ∴ x = 30 Initial quantity of mixture = 4x + x = 5x Initial quantity of mixture = 5 × 30 = 150 litres
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
