Question
A container contains 120 lit of pure milk and P liters
of water. Ratio of 25% of mixture to the initial quantity of water is 3 : 4 and when Q liters of water is added to it ratio of total mixture to water becomes 9 : 4. Then find the value of P + Q.Solution
(120 + P)/4P = 3/4
120 + P = 3P
P = 60 liters
And, (120 + Q)/(180 + Q) = 4/9
540 + 9Q = 720 + 4Q
5Q = 180
Q = 36 liters
Required sum = 96 liters
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