Question
A vessel contains mixture of milk and water mixed
in the ratio 11:5, respectively. 80 litres of the mixture is replaced with 30 litres of water such that the quantities of milk and water in the resultant mixture become equal. Find the initial quantity of mixture in the vessel.Solution
Let the initial quantities of milk and water in the vessel be 11x litres and 5x litres respectively.
80 litres mixture contains 55 litres milk and 25 litres water.
According to question:
11x – 55 = 5x – 25 + 30
6x = 60
x = 10
So the initial quantity of mixture = 16 × 10 = 160 litres
More Mixture Questions
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
(124.99)² = ?
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
181.87 ÷ 13.89 X 8.13 + ? = 11.852Â
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
1224.86% of √6399.98 = (399.99/4.99)% of (? ÷ 6.91 + 39.87)Â
24.11% of 249.99 + √143.97 ÷ 12.02 = ?