Question
The question below is based on the given series I. The
series I satisfy a certain pattern, follow the same pattern in series II and answer the questions given below. I: 1720, 1695, 1744, 1663, 1784, 1615 II: 690 ….. 754. If 754 is the nth term, what value should come in the place of (n + 1)th term.Solution
Answer: B Series I pattern: 1720 – 52 = 1695 1695 + 72 = 1744 1744 – 92 = 1663 1663 + 112 = 1784 1784 – 132 = 1615 Series II pattern: 690 – 52 = 665 665 + 72 = 714 714 – 92 = 633 633 + 112 = 754 (5th term) 754 – 132 = 585 (6th term)
(24% of 500 - 20) ÷ 25 = ? ÷ 4
52% of 36% of 810 = 72% of 18% of ?
13 X √? + 256 ÷ 4 = 30% of 900 - 50
If √3n 729, then the value of n is equal to:
18/2 of 3/9 of 2/6 of 69690 = ?
136% of 560 - 2/7 of 630 + 45% of 420 =?
7(1/7)% of 3500 + 6(2/3) % of 6000 = ? + 552.5
30, 39, 66, ? , 174, 255
- Evaluate: 210 ÷ 15 × 7 + 200 – 50% of 600