Question
What will be the value of 'R + S' in the series: 'Q',
'R', 60, 'S', 240, 'P + 6Q' Two number series 'l' and 'II' are given below. Both series have a missing term, if 'P' and 'Q' are natural numbers, then find their values and answer the questions based on it. l. 13, 95, 218, 'P' , 619, 913 II. 108, 122, 143, 178, (Q2 + 2)  , 304Solution
ATQ, For I: 13 + (92 + 1) = 95 95 + (112 + 2) = 218 218 + (132 + 3) = 390 390 + (152 + 4) = 619 619 + (172 + 5) = 913 So, 'A' = 390 For II: 108 + (2 X 7) = 122 122 + (3 X 7) = 143 143 + (5 X 7) = 178 178 + (7 X 7) = 227 277 + (7 X 11) = 304 So, Q2 + 2 = 227 Or, Q2 = 225 So, 'Q' = ±15 Since, 'Q' is a natural number, therefore 'Q' = 15. Q = 15 and P+6Q = 390+90 = 480 So, series is: 15, 'R',60,'S',240,480 15 x 2 = 30 --> 'R' 30 x 2 = 60 60 X 2 = 120 --> 'S' 120 x 2 = 240 240 x 2 = 480 So, required value = 'R+S' = 30+120 = 150
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