What will be the value of 'R + S' in the series: 'Q', 'R', 60, 'S', 240, 'P + 6Q'

ATQ, For I: 13 + (9² + 1) = 95 95 + (11² + 2) = 218 218 + (13² + 3) = 390 390 + (15² + 4) = 619 619 + (17² + 5) = 913 So, 'A' = 390 For II: 108 + (2 X 7) = 122 122 + (3 X 7) = 143 143 + (5 X 7) = 178 178 + (7 X 7) = 227 277 + (7 X 11) = 304 So, Q² + 2 = 227 Or, Q² = 225 So, 'Q' = ±15 Since, 'Q' is a natural number, therefore 'Q' = 15. Q = 15 and P+6Q = 390+90 = 480 So, series is: 15, 'R',60,'S',240,480 15 x 2 = 30 --> 'R' 30 x 2 = 60 60 X 2 = 120 --> 'S' 120 x 2 = 240 240 x 2 = 480 So, required value = 'R+S' = 30+120 = 150