Question
A Bullet is cylindrical up to a height of 40 cm and
conical above it. If its diameter is 35 cm and the slant height of the Conical part is 22cm, then the curved area of the bullet isSolution
Radius of Cone = 35/2 cm Curved Surface area of Conical Part of a bullet = πrl = 22/7×35/2 × 22 = 1210 cm² Curved Surface area of the Cylinder = 2πrh = 2 × 22/7×35/2 × 40 = 4400 cm² Total Surface area of a Bullet = 4400 + 1210 = 5610 cm²
351Â Â Â 261Â Â Â 181Â Â Â 111Â Â Â 51Â Â Â ?
Find the 31st term of the series 25, 29, 33……
632, 560, 494, 434, ?, 332
1331      1000            729       512       ?             216
...2556   636    156    ?    6
3 5 15 75 1125 ?
...1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
73920, 9240, ?, 220, 44, 11
12 78 385 ? 4629 9260
...A number series is given below, which follows a specific pattern. If 'A' represents the 'x'th term and 'B' represents ...
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