Question
A Bullet is cylindrical up to a height of 40 cm and
conical above it. If its diameter is 35 cm and the slant height of the Conical part is 22cm, then the curved area of the bullet isSolution
Radius of Cone = 35/2 cm Curved Surface area of Conical Part of a bullet = πrl = 22/7×35/2 × 22 = 1210 cm² Curved Surface area of the Cylinder = 2πrh = 2 × 22/7×35/2 × 40 = 4400 cm² Total Surface area of a Bullet = 4400 + 1210 = 5610 cm²
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