Question
A cylindrical vessel 32 cm high having 18 cm as the
radius of the base is filled with sand. This is emptied on the ground and a conical heap of sand is formed. If the height of the concial heap is 24 cm, the radius of base is:Solution
`pir^2h = 1/3piR^2H` `(18)^2xx32 = 1/3xxR^2xx24` `R^2 = ((18)^2xx32)/8` `R = 36cm`
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