Question
If perpendicular and base of a right-angle triangle are
12 cm and 16 cm respectively, then find the length of the shortest median of triangle.Solution
Using Pythagoras theorem, (Perpendicular)² + (Base)² = (Hypotenuse)² Or, 12² + 16² = (Hypotenuse)² Or, (Hypotenuse)² = 144 + 256 = 400 So, Hypotenuse = 20 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (20/2) = 10 cm Hence, option A
38    40    83    254    ?     5126
Find the wrong number in the given series.
3 1.5 1.5 ? 4.5 11.25
...If 7             16      x    90       171          292
Then, 2x 2 +  1 + x ...
98    219    75    244    ?    273
Find the maximum number of trees which can be planted, 25 meters apart, on the two sides of a straight road 2125 meters long
43 36 50 29 ? 22
...6Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â Â 32Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 249Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 240
104   106   110   113   ?   126
6 2 8 ? 84 416
...75    196    52    221    ?    250