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ATQ,
Outer radius of the pipe = 8 + 2 = 10 cm
Volume of the pipe = π × height × [(outer radius)² - (inner radius)²]
= (22/7) × 12 × (10² - 8²)
= (22/7) × 12 × (100 - 64)
= (22/7) × 12 × 36
= 1,123.71 cm³ or 1124 cm³
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