Question
Find the area of sector of a circle whose radius is 21
cm and angle subtended by the sector at centre of circle is 45 ° .Solution
Area of sector = (A/360) X π X radius 2  (Here 'A' is the angle subtended by sector at centre)
So, required area = (45/360) x (22/7) X 21 2 Â = 173.25 cm 2
`sqrt(7744)` Â Â -Â `sqrt(4761)` +Â `sqrt(8281)` Â +Â `sqrt(5625)` + ? = 1856Â
25% of 140 + 2 × 8 = ? + 9 × 5
What value should come in the place of (?) in the following questions?
320 + 162 – 55% of 720 = 5 * ?2
√10000 × √8100 - (50)² = √(?) + (80)²
33 × ?2 – 6 × 5 = 3270
(3/7) of 700 + 33(1/3)% of 339 - 69 =?
? % of 1200 = 20% of 30% of 3600
Simplify: 3√50 − 2√8 + √18
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
5/2 of 5/6 of 12/5 of 54 % of 5250 = ?