Question
A cuboidal box has a length of 15 cm, a width of 12 cm,
and a height of 10 cm. A cylindrical hole of radius 3 cm and height equal to the cuboid is drilled through its center. Find the remaining volume of the box.Solution
Volume of the cuboid = l × w × h = 15 × 12 × 10 = 1800 cm³. Volume of the cylindrical hole = πr²h = (22/7) × 3² × 10 = (22/7) × 9 × 10 = 282.86 cm³. Remaining volume = 1800 - 282.86 = 1517.14 cm³ ≈ 1517 cm³.
Statements: L < E; M = O; E >K ≥ M
Conclusions:
I. L < M
II. K = O
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