Question
Calculate the slant height of a right circular cone if
the volume is 1232 cm³ and the base area is 154 cm².Solution
Volume of cone = Area of base × height ÷ 3 So, height of the cone = 1232 ÷ 154 × 3 = 24 cm Area of the base = πr2 (Where ‘r’ is the radius) 154 = (22/7) × r × r Or, r2 = 49 So, r = 7 (As radius cannot be negative) Slant height of cone = √(radius2 + height2) So, slant height = √(72 + 242) = √(49 + 576) = 25 cm
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 252 = 0
Equation 2: y² - 30y + 221 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 5x + 6 = 0
Equation 2: y² - 7y + 12 = 0
I). 5p2 Â - p - 4 = 0
II). q2 - 12q + 27 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 19x² - 88x + 100 = 0
Equation 2: 17y² - 79y + 90...
I. 8x² - 78x + 169 = 0
II. 20y² - 117y + 169 = 0
l. x2 - 16x + 64 = 0
II. y2Â = 64
I. x² + 11x + 24 = 0
II. y² + 17y + 72 = 0
Solve both equations I & II and form a new equation III in variable ‘r’ (reduce to lowest possible factor) using roots of equation I and II as per ...
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