Question
The volume of a conical water tank is 4928 m³ and the
area of its base is 616 m². Find the length of the canvas required to build the tank if the width of the canvas is 2 meters.Solution
Πr2 = 616 22/7×r2= 616 R = 14 cm And now the volume of the conical tent = 4928 1/3πr2 h= 4928 1/3 ×22/7 × 196 ×h = 4928 h= ( 4928 ×7×3)/22× 196 =24m l = √ 576+196 = √ 772 =2 7.7 cm The area of the canvas required to build the tent = πr l Which will equal the area of the rectangular canvas. π r l = 2×length of canvas 22/7× 7× 27.7 = 2 × length of canvas length of canvas =11×2 7.7 = 304.7 m
15   8   9   15   32    ?    250.5
80    81.5    83.5     ?     89      92.5
...8      27       64      125     ?       343Â
...18, 21, 45, 138, 555, ?
135, 148, ?, 184, 207, 236
33Â Â Â 41Â Â Â 25Â Â Â 49Â Â Â 17Â Â Â Â ?
25   25   37.5   ?   328.125   1804.6875
120, 130, 145, 165, ?, 220
11    16    42    141    ?   2945   17700
...80, 116, 52, ?, 8, 204
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