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CF is the tangent segment, which is 15 cm. CD is the secant segment, which is 20 cm. DE is the chord we want to find. According to the Power of a Point theorem: CF2 = CD × CE Since CD = CE + ED and CE =CD-DE, we can rewrite the equation as 152 = 20 × (20- DE) Now, 225 /20=20-DE 11.25 =20-DE DE =20-11.25 =8.75 The length of the chord DE is 8.75cm,
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