On a rectangular wall of length 35 metres and height 30 metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 10 metres and length of altitude of the triangle is 8 metres, then excluding the window, what is the surface area of the wall?(in cm 2)
Surface area of the entire wall = length × height = 35 × 30 = 1050 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 102 + (1/2) × 10 × 8 => 100 + 40 = 140m2 Required surface area = 1050 – 140 = 910m2
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