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Solution- R =15cm, r= 5/2cm, h =6cm Volume of hemispherical bowl = (2/3) πR3 volume of hemispherical bowl =Numbers of bottles ×volume of 1 bottle (2/3) πR3 = N × πr2h N = (2/3) πR3 / πr2h = [(2/3) ×15×15×15] / [(5/2) × (5/2) ×6] N= 60
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