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Let side of 4 squares be a, b, c and d cm respectively. => a = 24/4 = 6 cm => b = 36/4 = 9 cm => c = 40/4 = 10 cm => c = 44/4 = 11 cm Perimeter of new square = a + b + c + d = 36 => side = 36/4 = 9 cm Required area = side2 = 92 = 81 cm2.
If (a - b - c) = 6, and (ab - bc + ca) = 117, then find the value of (a 2 + b 2 + c 2 )
If a + b + c = 6, a³ + b³ + c³-3abc = 342, then what is the value of ab + bc + ca
If 4x + 1/3x = 12 then find the value of 9x2 +1/16x2.
If x = 19 , find x 5 - 20 x 4 + 20 x 3 - 20x 2 + 20x - 20 = ?
ABCD is a cyclic quadrilateral in which AB =16.5 cm. BC = x cm. CD= 11 cm. AD 19.8 cm, and BD is bisected by AC at O. What is the value of x?
If 4x² + y² = 25 and x y = 6, then find the value of 2x + y?