A circle is inscribed in a square an equilateral triangle of side 6√2 cm is inscribed in that circle the length of the diagonal of the square is-
Let the side of square is a Then radius of circle=a/2 Given- Side of equilateral triangle = 6√2cm radius of circle =Side of equilateral triangle a/2 = 6√2/√2 a=12cm Diagonal of square= side √2 =12√2cm
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