Question
The perimeter of a sector of a circle, whose radius is
22 cm, is 64 cm. If the length of a rectangle is 10 cm more than the arc subtended by the sector and its perimeter is 80 cm, then find the area (in cm2) of the rectangle.Solution
Let the arc subtended by the sector be ‘l’ cm and the radius of the circle be ‘r’ cm According to the question, (l + 2r) = 64 Or, l = 64 – 2r = 64 – (2 × 22) = 20 cm Therefore, length of the rectangle = 20 + 10 = 30 cm Let the breadth of the rectangle be ‘b’ cm Therefore, 2 × (30 + b) = 80 Or, b = 40 – 30 = 10 cm Therefore, area of the rectangle = length × breadth = 10 × 30 = 300 cm2
Statements: M = N; A < C < E; N > A
Conclusions:
I. E > N
II. M > C
Statements: B ≥ C > D ≤ E ≤ F ≤ G
Conclusions:I. D = G II. D < G
Which of the following symbols should replace the sign ($) and (#) in the given expression in order to make the expressions V ≥ Y and X > B definitel...
In the following question the relationship between different elements is given in the statements followed by two conclusions I and II. Read the stateme...
Statements:
Y $ N * G © J @ Q
Conclusions:
I. G @ Q
II. Q * Y
III. Q % G
Statements: B ≤ C = T; Z ≥ N ≥ D > K ≥ T
Conclusions:
I. C < N
II. B ≤ K
III. N > B
...Statement: Q > P; R > S > O; R < P
Conclusion:
I.Q > O
II. Q > S
Statements: G < B ≤ T < U = F ≥ S
Conclusion: I. S ≤ T II. F > B
...- How is L related to O?
Statements: 4 > 7 > 9; 1 ≤ 4 < 5; 7 > 6 = 2 > 3
Conclusions:
I. 3 < 4
II. 9 < 5
III. 1 < 6
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