Question
On a rectangular wall of length 23 metres and height 22
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 12 metres and length of altitude of the triangle is 3 metres, then excluding the window, what is the surface area (in m2) of the wall?Solution
Surface area of the entire wall = length × height = 23 × 22 = 506 m2 Surface area of the window = Sum of surface area of the square part + surface area of the triangular part = 122 + (1/2) × 12 × 3 = 144 + 18 = 162 m2 So, desired surface area = 506 – 162 = 344 m2
More Mensuration Questions
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2
