Question
The perimeter of a rectangular field is 60 metres and
its area is 137.5 m2 . What is the length of the diagonal of this field?Solution
Let the length and breadth of the rectangular field be ‘p’ metres and ‘q’ metres respectively Then, according to the question, 2 × (p + q) = 60 Or, (p + q) = 60/2 = 30…… (1) Also p × q = 137.5 We know, (p + q)2 = p2 + q2 + 2pq Or, p2 + q2 = 302 – 2 × 137.5 Or, p2 + q2 = 625 So, length of the diagonal of the rectangular field = √(length2 + breadth2) = √(p2 + q2) = √625 = 25 metres
If p = 24 - q - r and pq + r(q + p) = 132, then find the value of (p² + q² + r²).
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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Find the value of the given expression-
(4x+4 -5× 4x+2) / 15×4x – 22×4x
If 4x² + y² = 40 and x y = 6, then find the value
of 2x + y?
If p = 40 - q - r and pq + r(q + p) = 432, then find the value of (p² + q² + r²).
47.98 × 4.16 + √325 × 12.91 + ? = 79.93 × 5.91
If x + y = 4 and (1/x) + (1/y) = 24/7, then the value of (x3 + y3).
- If p = 20 - q - r and pq + r(p + q) = 154, then find the value of (p² + q² + r²).
If a = (√2 - 1)1/3, then the value of (a-1/a)3 +3(a-1/a) is:
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