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Area of the track = length of track x breadth of track = 80 x breadth of track = 2400 So, breadth of track = 2400 ÷ 80 = 30 So, perimeter of the track = (80 + 30) x 2 = 220 metres So, speed of the car = (220/20) = 11 m/s Relative speed of the car with respect to the person = 11 + 5 = 16 m/s So, distance between the car and the person, 3 seconds before they cross each other = 16 x 3 = 48 metres
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