Question
On a rectangular wall of length 20 metres and height 15
metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 8 metres and length of altitude of the triangle is 5 metres, then excluding the window, what is the surface area of the wall?Solution
Surface area of the entire wall = length × height = 20 × 15 = 300 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 82 + (1/2) × 8 × 5 => 64 + 20 = 84 m2 Required surface area = 300 – 84 = 216 m2
I. 15y2 + 4y – 4 = 0
II. 15x2 + x – 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 15b2 + 26b + 8 = 0
II. 20a2 + 7a - 6 = 0
I. x2 – 12x + 32 = 0
II. y2 + y - 20 = 0
I. 6y2 - 17y + 12 = 0
II. 15x2 - 38x + 24 = 0
I. 4x2 – 53x – 105 = 0
II. 3y2 – 25y + 48 = 0
I. 9/(4 )p + 7/8p = 21/12
II. 7/5p = 9/10q + 1/4
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
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