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      Question

      On a rectangular wall of length 26 metres and height 21

      metres, there is a window in the shape of triangle surmounted on a square. If the base of triangle and square overlap and length of each side of the square is 9 metres and length of altitude of the triangle is 6 metres, then excluding the window, what is the surface area of the wall?
      A 438 sq.m Correct Answer Incorrect Answer
      B 416 sq.m Correct Answer Incorrect Answer
      C 408 sq.m Correct Answer Incorrect Answer
      D 424 sq.m Correct Answer Incorrect Answer

      Solution

      Surface area of the entire wall = length × height = 26 × 21 = 546 m2 Surface area of the window = sum of surface area of the square part + surface area of the triangular part => 92 + (1/2) × 9 × 6 => 81 + 27 = 108 m2 Required surface area = 546 – 108 = 438 m2

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