Question
The average weight of five friends A, B, C, D and E is
(x+8) years while the average weight of C and E is (x-8) kg. If the weight of another person F is also added, then average weight of all of them is reduced by 7 kg. Find the value of ‘x’ if average weight of A, B, D and F is 92.5 kg.Solution
Total weight of friends A, B, C, D and E = 5(x+8) kg So, Total weight of A, B and D = 5(x+8) - 2(x-8) = (3x+56) kg Weight of F = [(x+8-7)×6] - [5(x+8)] => F = (x-34) kg According to the question, => (3x+56) + (x-34) = 92.5 × 4 => 4x + 22 = 370 => 4x = 348 => x = 87
24.96% of 380 + ? – 169.99 = 149.99% of 80
25.05% of 220.05 – 10.15% of 119.99 × 2.02 = ?
What approximate value will replace the question mark (?) in the following?
√57...
What approximate value should come in the place of question mark (?) in the following questions?
(12.99)² + √( ? x 24.99) - (3.99)³ = 113.99 ...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(5.08/3.01) of 41.99 - 24.99% of 120.09 = ? - 9.99
What approximate value should come in the place of question mark (?) in the following questions?
(1785.99 / 2.98) + (2449.89 / 6.99) - 49.99 x 4.01 = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
