Question
Mr. Shiva invested equal amount of money in two private
firms which gives 15% simple interest per annum for 3.5 years and 5 years respectively. If the difference in their interests is Rs. 315. The amount invested by Mr. Shiva in each firm is:Solution
Let’s assume he invested Rs. x each in both firms. We know that Simple interest = (P × R × T)/100 Where, P = principal, R = % rate of interest, T = time in years For both investments, P = x, R = 15 T = 3.5 for first investment and T = 5 for second investment. According to question, => [(x × 15 × 5)/100] - [ (x × 15 × 3.5)/100] = 315 => [(30x - 21x )/40] = 315 ⇒ x = 315 × (40/9) = 1400 ∴ He invested Rs. 1400 in each firm.
I. 6 y² + 11 y – 7= 0
II. 21 x² + 5 x – 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. 2x² - 15x  + 13 = 0
II. 3y² - 6y + 3 = 0
I. 2x² - 7x + 3 = 0
II. 8y² - 14y + 5 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x2 + 6√7x - 315 = 0    Â
E...
I. 35x² - 51x + 18 = 0
II. 30y² + 17y – 21 = 0
I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 2y2 - 37y + 143 = 0
II. 2x2 + 15x – 143 = 0
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
Relevant for Exams:
