A 18 m long ladder (whose foot is on the ground) leans against a wall making an angle of 60° with the wall. What is the height (in m) of the point where the ladder touches the wall from the ground?

In ΔABC ∠C = 180^{∘} − 30^{∘} − 90^{∘} ∠C = 60° Now, sin 60^{∘} = AB/AC √3/2 = AB/18 ⇒ AB = 9√3

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