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Start learning 50% faster. Sign in nowLet amount Rs. x lent at 6% p. a Amount lent at 4% p. a = (21500 – x) As we know, SI = P × r × t/100 Simple interest for 7/2 year = Rs.3521 Simple interest for 1 year = 3521 × 2/7 = 1006 According to the question (x × 6 × 1)/100 + [(21500 – x) × 4 × 1]/100 = 1006 ⇒ 6x + 86000 – 4x = 100600 ⇒ 2x = 100600 – 86000 ⇒ x = 14600/2 ⇒ x = 7300 ∴ The sum lent at 6% per annum is Rs. 7300
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0