Question
The ratio of the length of a rectangle, breadth of the
rectangle and the diameter of a circle is 12:11:14. If the area of the circle is 616 cm2 , then what is the difference between the circumference of the circle and the perimeter of the rectangle?Solution
Area of the circle = pi;r2 616 = 22/7 times; r2 r2 = 196 r = 14 cm (Since, radius cannot be negative) Radius of the circle = 14 cm Diameter of the circle = 2r = 28 cm Length of the rectangle = (28/14) times; 12 = 24 cm Breadth of the rectangle = (28/14) times; 11 = 22 cm Perimeter of the rectangle = 2 times; (24 + 22) = 92 cm Circumference of the circle = 2 times; (22/7) times; 14 = 88 cm Required difference = 92 ndash; 88 = 4 cm
I. p2 - 19p + 88 = 0  Â
II. q2Â - 48q + 576 = 0
What will be the product of smaller roots of both equations.Â
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
I. x2 + 24x + 143 = 0
II. y2 + 12y + 35 = 0
I. 27x6-152x3+125=0
II. 216y6Â -91y3+8=0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
I. x2-2x- √5x+2√5 = 0
II. y2-√3 y- √2 y+ √6 = 0
...I. 2x2 – 25x + 33 = 0
II. 3y2 + 40y + 48 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
