The diameter of a sphere is twice the diameter of another sphere, The surface area of the first sphere is equal to the volume of the second sphere, The magnitude of the radius of the first sphere is
let radius of sphere 1 = r1 radius of sphere 2 = r2 Given, r1 = 2 r2 surface area of sphere 1 = volume of sphere 2 4π(r1)2 = 4/3 π(r2)3 r1 = 2 r2 4π(2r2)2 = 4/3 π(r2)3 4 = 1/3(r2) r2 = 12 r1 = 2 r2 = 2 × 12 = 24
0.25 x 696 ÷ 0.3 = ?
12 % of 72 × 25 – (x ÷ 20) × (16 ÷ 24) × 36 + 1/5 × x = (4 ÷ 12) × 36 ÷ 1/4
2850 ÷ 2.5 - ? × 42 = 300
(82 + 62 ) × 1.25 + 20% of 145 = ? – 40% of 65
4.5 times 5/0.9× 35% of 240 =?
√? + √1296 + √729 = 464/4
16 × ? + 36% of 250 = 410
2*1/3 + 22*1/3 + 222*1/3 + 2222*1/2 + 22222*1/2 = ?
14 × 11 + 25 – ? = 21% of 300
