Question
A cylindrical rod of length h is melted and cast
into a cone of base radius twice that of the cylinder. What is the height of the cone ?Solution
Let the radius of cylinder be r and radius of cone be R given, R = 2r Let height of cylinder be h and height of cone be H. According to question, volume of cylinder = volume ofcone ` ` = `pir^2h=1/3pi(2r)^2H` h = 4H/3 on solving we get, H = `(3h)/4`
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