Question
If the side of square and its area is in the ratio of
7:28 then find its perimeter?Solution
Let the side of square = a cm. According to the question a:a2 = 7 : 28 ………….(1) ⇒ a = 28/7 cm Side = 4 cm Perimeter of square = 4 x side of square Perimeter of square = 4 x 4 = 16 cm
Determined the simplified value of the given expression:(1 - sin2 q) X (sec q + tan q) X (sec q - tan q) X cosec2 q
If (sinθ+cosθ)/(sinθ-cosθ) = 2, then the value of sin4 θ is
Find the simplified value of:
(tan 40 º + tan 20 º )/(1 - tan 40 º tan 20 º)
- Find the simplified value of the expression:sin 2 45 o + sin 2 60 o - (1/3) X tan 2 60 o
If Sin θ + Cos θ = √2 Cos(90 - θ ), then find the value of Cot θ ?
...The Value of (sin38˚)/(cos52˚) + (cos12˚)/(sin78˚) - 4cos²60˚ is
If √3cosec 2x = 2, then the value of x:
A ladder is leaning against a wall, making an angle of 60° with the ground. The top of the ladder reaches a window 15 meters above the ground. Find the...
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...If 2x = cosec @ and 4/x = cot @ then the value of 2(x ² - 1/x ² ) is
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