Question
If a triangle with base 15 cm has the same area as a
circle with radius 15 cm, then the corresponding altitude (in cm) of the triangle is:ÂSolution
Using formula Area of triangle = 1/2 x base x height and Area of circle = πr2, Let the corresponding altitude of the triangle = a cm. According to the question, Area of the triangle = Area of the circle ⇒ 1a/2 x 15 = π x 15 x 15 ⇒a = 2 x 15 π ⇒a = 30 π cm
I. 2y² - 3y – 14 = 0
II. 3x² - 7x + 4 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
I. √(17x) + √51 = 0  Â
II. √(4y) + 3 = 0
If the roots of the quadratic equation 5x² + 4x + 6 = 0 are α and β, then what is the value of [(1/α) + (1/β)]?
...I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
I. 2x2 + 12x + 18 = 0
II. 3y2 + 13y + 12 = 0
I. 5x2 – 18x + 16 = 0
II. 3y2 – 35y - 52 = 0
I. 63x² + 146x + 80 = 0
II. 42y² + 109y + 70 = 0
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