Question
Find the maximum people that a company can recruit, if
the recruit function is given by p(x) = 41 β 24x β 18x2Solution
The recruit function is given as p(x) = 41 β 24x β 18x2 Therefore, pβ(x) = - 24 - 36x Pββ(x) = -36 Now, pβ(x) = 0 => x = -24/36 = -2/3 Also, Pββ(-2/3) = -36 < 0 By second derivative test, x = -2/3 is the point of local maxima of p. Therefore, Maximum profit = p(-2/3) => 41 β 24(-2/3) β 18(-2/3)2 Β => 41 + 16 β 8 = 49 Hence, the maximum recruit that the company can make is 49 people.
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