Login / Signup

Menu

Previous Year Paper
Exams
Online Course
Free Mock Test
General Awareness
Daily Practice
All Courses
Testimonials

Home
/Questions
/Quantitative Aptitude
/Limits and Continuity
/Evaluate the limit: ...

Question

Evaluate the limit:

A -6 Correct Incorrect

B -4 Correct Incorrect

C -3 Correct Incorrect

Detailed Solution

ATQ, Use the identity: sin(3x) = 3·sin(x) − 4·sin³(x) So, sin(3x) − 3·sin(x) = [3·sin(x) − 4·sin³(x)] − 3·sin(x) = −4·sin³(x) Therefore the limit becomes: lim (x → 0) [ sin(3x) − 3·sin(x) ] / x³ = lim (x → 0) [ −4·sin³(x) / x³ ] = −4 · lim (x → 0) [ (sin(x)/x)³ ] We know: lim (x → 0) sin(x)/x = 1 So: −4 · lim (x → 0) [ (sin(x)/x)³ ] = −4 · 1³ = −4

Practice Next

More Limits and Continuity Questions

aₙ = (1/2ⁿ) + (1/3ⁿ). Find limit as n→∞.
Question 2
Question 3
Question 4
Question 5
Evaluate the limit:
Evaluate lim₍ₓ→0₎ ( √(1 + 2x) − √(1 − 3x) ) / x
Question 8
Question 9
Evaluate the limit: lim (x→2) [(x² – 4) / (x – 2)]

Hey! Ask a query

Please enter email id The email must be a valid email address.

Please enter Mobile Number Please enter valid Mobile Number

Please enter your Doubt

ask-question

Thank You for posting your query. Please check your email for further guidance.

Please Register/Login

Login or create an account to download this question.

Google Play Store

Apple App Store

+91 92055 24028 Available Mon-Sat (10 AM to 7 PM)

[email protected]

© ATOZLEARN EDUTECH PRIVATE LIMITED
All rights reserved.

Privacy & Policy