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(A + B + C) × 18 = 2700 Rs. Wages of (A + B + C) for 1day = 150 Rs. (A+C) × 10 = 940 RS Wages of (A + C) for 1 day = 94 Rs (B+C) x 20 = 1520 Wages of (B + C) for 1 day = 76 Wage of (A + C + B + C) for 1 day = 94 + 76 = 170 Per day Wages of C = 170 – 150 = 20 Rs.
Two numbers add up to 18, and the sum of their reciprocals is 5/2. Calculate the square of the product of the two numbers.
Find the median of 5, 6, 10, 7, 7, 8, 6, 5 and 12.
A number leaves a remainder of 12 when divided by 19. What will be the remainder when three times that number is divided by 19?
The smallest natural number that must be added to 1212 to make it a perfect square is:
Find the sum of all those 3-digit numbers which when divided by 10 leave a remainder of 5.
If (64)2 – (36)2 = 20Z, the value of z is
What should come in place of the question mark (?) in the following question?
956 × 753 = ?
