Question

From the top of a tower of height 40 feet, the angles of depression of two objects south and north of the tower are both 45°. What is the distance between the two objects (in feet)?

Q: From the top of a tower of height 40 feet, the angles of depression of two objects south and north o

In ΔABC, tan 45° = 40/CB ⇒ 1 = 40/CB ⇒ CB = 40 feet In ΔABD, tan 45° = 40/BD ⇒ 1 = 40/BD ⇒ BD = 40 feet CD = CB + BD = 40 + 40 = 80 feet

A 40√2

B 80

C 80√2

D 160

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Question

From the top of a tower of height 40 feet, the angles of depression of two objects south and north of the tower are both 45°. What is the distance between the two objects (in feet)?

Solution

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