Question

The LCM of two numbers is 21 times their HCF. The sum of HCF and LCM of these numbers is 176 .If one of the numbers is 56, find the other number. 

A 28 Correct Answer Incorrect Answer
B 24 Correct Answer Incorrect Answer
C 20 Correct Answer Incorrect Answer
D 32 Correct Answer Incorrect Answer
E None of these Correct Answer Incorrect Answer

Solution

Let HCF be  x , then LCM = 21 It is given, LCM + HCF = 176               ⇒x  + 21x  = 176    ⇒ 22x = 176         x = `176/22=` 8 HCF = x  = 8 and LCM = 21x  = 21 `xx` 8 = 168 Product of two numbers = Product of their HCF and LCM 56  `xx` other number = 8 `xx`  168  Other number =`(8xx168)/56` = 24

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