Question

The product of two numbers is 972 and their HCF is 9. Total number of such pairs of numbers is?

A 3 Correct Answer Incorrect Answer
B 4 Correct Answer Incorrect Answer
C 1 Correct Answer Incorrect Answer
D 2 Correct Answer Incorrect Answer

Solution

As HCF is 9 so let numbers be 9x & 9y. It means x & y must be co-prime. Now 9x × 9y = 972, So xy = 12. Now pairs of (x, y) can be (1,12) , (2,6) & (3,4). Here only (1,12) & (3,4) are co-prime so number of pairs are 2.

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