Question
Solution
As HCF is 13 so let numbers be 13x & 13y. It means x & y must be co-prime. Now 13x+ 13y = 104, So x + y = 8. Now pairs of (x , y) can be (1,7) , (2,6) , (3, 5) & (4,4) but (2,6) and (4,4) are not co-prime hence number of pairs are 2.
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