Question
Solution
As HCF is 13 so let numbers be 13x & 13y. It means x & y must be co-prime. Now 13x+ 13y = 104, So x + y = 8. Now pairs of (x , y) can be (1,7) , (2,6) , (3, 5) & (4,4) but (2,6) and (4,4) are not co-prime hence number of pairs are 2.
2 3 4 15 56 ?
...In each of the following questions the number series is given. One term of the series is denoted by x. You have to calculate of value of x and by using ...
24 25 46 ? 572 2885
...34, 18, 20, ?, 70, 180
Complete the series.
19, 23, 26, 30, 33, ?
4 5 12 39 160 ?
...24 47 137 ? 2679 16049
...51     53     109     332     ?     6686
...4 , 3, 4 , ? , 32
6 6 13 39 ? 226
...