Let AB = AC = a cm. BD = DC = b cm. Altitude of isosceles triangle is also median. In right ∆ADC, 6² = a² - b² 36 = a² - b² ………… (i) Perimeter = 36 a + a + 2b = 36 2a + 2b = 36 a + b = 18 ………. (ii) On dividing (i) & (ii) we get, (a² - b² )/(a+b) = 36/18 = 2 ((a+b) (a-b))/((a+b)) = 2 a – b = 2 a + b = 18 on solving, 2a = 20 a = 10 b = 8 BC = 16 Area of ∆ABC = 1/2 × AD × BC = 1/2 × 6 × 16 = 48 cm²
3, 10, 29, 66, ?
40 41 37 46 ? 55 19
...4 10 ? 62.5 156.25 390.625
...1, 7, 25, 61, ?
625, 125, 375, 75, 225, 45, ?
58, 63, 78, ?, 138, 183
98, 134, 198, ?, 442, 638
58, 67, ?, 76, 40, 85
4097, ?, 4359, 4493, 4629, 4767
What will come in place of the question mark (?) in the following series?
2, 5, 14, 41, 122, 365, ?
