Question
∆PQR is an isosceles right angled triangle with ∠Q
= 90°. On the sides PR and PQ, two equilateral triangles PRS and PQT have been constructed. The ratio of area of ∆ PQT and ∆PRS isSolution
Let PQ = PR = 1 PR = √(12+1²) = √2 (using Pythagoras) (Area of (∆PQT))/(Area of (∆PRS)) = (√3/4 (1)²)/(√3/4 (√2)²) = 1/2 = 1 : 2
(√1157 + 10.15% of 159.89) × 4.85 + 150.25 = ? × 19.67
{(√2305) % of 74.69} × 15.21 - 27.89 × 44.88 + 45.12% of 2399.87
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
(124.99)² = ?
? * 4.89 = (410.15 ÷ 13.97) % of 6190 - 1342.77
181.87 ÷ 13.89 X 8.13 + ? = 11.852
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
180.25 × 14.995 ÷ √26 = ? × 5.985
1224.86% of √6399.98 = (399.99/4.99)% of (? ÷ 6.91 + 39.87)
24.11% of 249.99 + √143.97 ÷ 12.02 = ?