Question
∆PQR is an isosceles right angled triangle with ∠Q = 90°. On the sides PR and PQ, two equilateral triangles PRS and PQT have been constructed. The ratio of area of ∆ PQT and ∆PRS is
Solution
Let PQ = PR = 1 PR = √(12+1²) = √2 (using Pythagoras) (Area of (∆PQT))/(Area of (∆PRS)) = (√3/4 (1)²)/(√3/4 (√2)²) = 1/2 = 1 : 2
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