Question
PQRS is a cyclic quadrilateral of which PQ is the
diameter. Diagonals PR and QS intersect at A. If SQR = 25°, then angle PAS measuresSolution
∠PSQ = 90° ( angle made from the diameter) So ∆PSQ is a right angled triangle. Similarly, ∠PRQ = 90° Now in ∆ARQ ∠ARQ + ∠AQR + ∠QAR = 180° 90°+ 25° + ∠QAR = 180° ∠QAR = 65° ∠QAR = ∠PAS = 65°
More Geometry Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
Relevant for Exams:
